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· CIE 0580 Topic Guide · 4 min read

IGCSE Percentage Problems: Every Type You'll See in the Exam

Percentage increase, decrease, reverse percentages, and compound interest — all in one guide.

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    Percentage questions appear in every IGCSE maths exam, across multiple papers. They range from $1$-mark calculations to $5$-mark compound interest problems. Here is every type, with the exact method examiners expect.

    Type 1: Finding a Percentage of an Amount

    Method: $\text{Amount} \times \frac{\text{percentage}}{100}$

    Example: Find $15\%$ of $240$.

    $240 \times \frac{15}{100} = 240 \times 0.15 = 36$

    This is the simplest type. The common mistake is forgetting to divide by $100$.

    Type 2: Percentage Increase and Decrease

    Increase: $\text{New value} = \text{Original} \times (1 + \frac{r}{100})$

    Decrease: $\text{New value} = \text{Original} \times (1 - \frac{r}{100})$

    Example: A shirt costs $80$. It is reduced by $30\%$. Find the sale price.

    $80 \times (1 - \frac{30}{100}) = 80 \times 0.70 = 56$

    Multiplier shortcut:

    Change Multiplier
    Increase by $5\%$ $\times 1.05$
    Increase by $12\%$ $\times 1.12$
    Decrease by $20\%$ $\times 0.80$
    Decrease by $35\%$ $\times 0.65$

    Type 3: Expressing One Quantity as a Percentage of Another

    Method: $\frac{\text{Part}}{\text{Whole}} \times 100$

    Example: $45$ students out of $180$ chose maths. What percentage is this?

    $\frac{45}{180} \times 100 = 25\%$

    Common mistake: Dividing the wrong way round. The “whole” is always the total or the reference amount.

    Type 4: Percentage Change

    Method: $\frac{\text{New} - \text{Original}}{\text{Original}} \times 100$

    Example: A house price increased from $250000$ to $285000$. Find the percentage increase.

    $\frac{285000 - 250000}{250000} \times 100 = \frac{35000}{250000} \times 100 = 14\%$

    Watch: The denominator is always the original value, not the new value.

    Type 5: Reverse Percentage (Finding the Original)

    This is the type most students struggle with. You’re given the final amount after a percentage change and must find the original.

    Method: $\text{Final amount} \div (1 \pm \frac{r}{100})$

    Example: After a $20\%$ increase, a TV costs $360$. Find the original price.

    $360 \div 1.20 = 300$

    Example: After a $15\%$ discount, a bag costs $170$. Find the original price.

    $170 \div 0.85 = 200$

    The critical mistake: Students calculate $20\%$ of $360$ and subtract it. This gives $288$, which is wrong. The $20\%$ was applied to the original, not to $360$.

    Type 6: Compound Interest

    Formula: $A = P\left(1 + \frac{r}{100}\right)^n$

    Where:

    • $A$ = final amount
    • $P$ = principal (starting amount)
    • $r$ = annual interest rate
    • $n$ = number of years

    Example: $5000$ is invested at $3\%$ per year compound interest for $4$ years.

    $A = 5000 \times (1 + \frac{3}{100})^4$ $= 5000 \times 1.03^4$ $= 5000 \times 1.12550881$ $= 5627.54$ (2 d.p.)

    Interest earned: $5627.54 - 5000 = 627.54$

    Compound vs Simple Interest

    Feature Simple Compound
    Formula $P + Prn$ $P(1+\frac{r}{100})^n$
    Interest on Original only Previous balance
    Growth Linear Exponential

    Exam tip: If the question says “compound interest”, always use the exponential formula. Never multiply by $n$.

    Type 7: Depreciation

    Same as compound interest but with decrease:

    Formula: $V = P\left(1 - \frac{r}{100}\right)^n$

    Example: A car worth $20000$ depreciates at $12\%$ per year for $3$ years.

    $V = 20000 \times (1 - \frac{12}{100})^3$ $= 20000 \times 0.88^3$ $= 20000 \times 0.681472$ $= 13629.44$

    Type 8: Finding the Rate or Time

    Given the formula $A = P(1 + \frac{r}{100})^n$, you may need to find $r$ or $n$.

    Finding $n$ (number of years): Use trial and improvement or logarithms (if allowed).

    Example: $1000$ grows to $1200$ at $5\%$ compound interest. How many years?

    $1200 = 1000 \times 1.05^n$ $1.2 = 1.05^n$ $n=3$: $1.05^3 = 1.157625$ (too low) $n=4$: $1.05^4 = 1.21550625$ (above $1.2$)

    Answer: $4$ complete years needed.


    Practice Percentage Problems

    Related guides: Edexcel 4MA1: Ratio & Percentage Mistakes · Paper 4: 10 Tips to Gain 20+ Marks · IGCSE Trigonometry Complete Guide

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